x^2+(6/5x)+(144/25)=(179/25)

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Solution for x^2+(6/5x)+(144/25)=(179/25) equation: 



x^2+(6/5x)+(144/25)=(179/25)

We move all terms to the left:

x^2+(6/5x)+(144/25)-((179/25))=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x^2+(+6/5x)+(+144/25)-((+179/25))=0

We get rid of parentheses

x^2+6/5x+144/25-((+179/25))=0

We calculate fractions


x^2+()/6250x^2+720x/6250x^2+(-((+179*5x)/6250x^2=0

We multiply all the terms by the denominator


x^2*6250x^2+720x+(-((+179*5x)+()=0



We calculate terms in parentheses: +(-((+179*5x)+(), so:

-((+179*5x)+(



Wy multiply elements

6250x^4+720x+(-((+179*5x)+()=0



We calculate terms in parentheses: +(-((+179*5x)+(), so:

-((+179*5x)+(



We do not support expression: x^4

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